Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Input: "Hello World" Output: 5
implSolution{pubfnlength_of_last_word(s:String) -> i32{letmut cnt = 0;letmut flag = false;for c in s.chars(){if c == ' '{ flag = true;}elseif flag { cnt = 1; flag = false;}else{ cnt += 1;}} cnt }}